How do you solve for these identities:
1-sin^2è/cosè= cosè
sin^4è-cos^4è=2sin^2è-1
2 answers
that e symbol is suppose to be theta.
LS
= 1-sin^2Ø/cosØ
= cos^2 Ø/cos
= cos Ø = RS
Ls
= sin^4Ø-cos^4Ø
= (sin^2Ø + cos^2Ø)(sin^2Ø - cos^2Ø)
= 1( sin^2Ø - (1-sin^2Ø))
= 2sin^2Ø - 1
= RS
= 1-sin^2Ø/cosØ
= cos^2 Ø/cos
= cos Ø = RS
Ls
= sin^4Ø-cos^4Ø
= (sin^2Ø + cos^2Ø)(sin^2Ø - cos^2Ø)
= 1( sin^2Ø - (1-sin^2Ø))
= 2sin^2Ø - 1
= RS