Asked by Anonymous
how do you sketch the curve represented by
x=(√t2+2)
y=t/4?
x=(√t2+2)
y=t/4?
Answers
Answered by
Steve
just like the other one!
pick some values for t, calculate x and y, and plot the points.
First, decide whether you meant
x=?(t^2+2)
or
x=?t^2 + 2)
I suspect the former, since ?t^2 = |t|
So, x is basically just t
y is basically just t.
The graph will be almost a straight line as x gets large. To wit:
http://www.wolframalpha.com/input/?i=parametric+plot+x%3D%E2%88%9A(t%5E2%2B2),+y%3Dt%2F4
Looks like a branch of an hyperbola, no? Let's see
t = 4y
x=?(t^2+2)
=?(y^2/16+2)
x^2 = y^2/16 + 2
x^2/2 - y^2/32 = 1
Yep - an hyperbola. For large x, the graph approaches the asymptotes.
pick some values for t, calculate x and y, and plot the points.
First, decide whether you meant
x=?(t^2+2)
or
x=?t^2 + 2)
I suspect the former, since ?t^2 = |t|
So, x is basically just t
y is basically just t.
The graph will be almost a straight line as x gets large. To wit:
http://www.wolframalpha.com/input/?i=parametric+plot+x%3D%E2%88%9A(t%5E2%2B2),+y%3Dt%2F4
Looks like a branch of an hyperbola, no? Let's see
t = 4y
x=?(t^2+2)
=?(y^2/16+2)
x^2 = y^2/16 + 2
x^2/2 - y^2/32 = 1
Yep - an hyperbola. For large x, the graph approaches the asymptotes.
Answered by
Steve
you can either
(a) find and fix my typo
(b) read bobpursley's solution, which is correct.
(a) find and fix my typo
(b) read bobpursley's solution, which is correct.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.