how do you simplify
|4x + 8 - 10| ≥ 6 ?
because i got x ≤ 2 and x ≥ -6 as the answer.
But, someone else got x ≤ 2 and x ≥ -1..
(because they simplified by subtracting 8 to 10)
(it is absolute value)
so, i thought that you would add 10 to 6 to make |4x + 8| ≥ 6, but i noticed that some person subtracted 10 by 8 to make |4x + 2| ≥ 6 . So, i am wondering, how to simplify it?
4 answers
i have to simplify it to get it into the |ax + b| < c format, so that is why i must ask.
|4x + 8 - 10| ≥ 6
|4x -2| ≥ 6
4x-2 ≥ 6 OR -4x+2 ≥ 6
4x ≥ 8 OR -4x ≥ 4
x ≥ 2 OR x ≤ -1
|4x -2| ≥ 6
4x-2 ≥ 6 OR -4x+2 ≥ 6
4x ≥ 8 OR -4x ≥ 4
x ≥ 2 OR x ≤ -1
so you would subtract 8 by 10? not add 10 to 6?
order of operation: the | ...| acts like a bracket, so you have to do inside the bracket first.