How do you set up this problem? Calculate the volume , in ml of a 0.150 M NaOH soulution needed to neutralize 25.0ml of a 0.288 M HCl solution?

Answer 1

Since each mole of HCl neutralizes 1 mole of NaOH,

.025L * .288M = 0.0072 moles HCl
So, for the NaOH,

0.0072 moles / 0.150M = .048L or 48 ml