how do you make 0.2M KI from 2M KI, what is the procedure?

Answer 1

The 2M mixture contains 2 moles of KI per liter volume. That amounts to 2x166 = 312 g of KI per liter. What you want is a mixture with 1/10 as much KI per liter.

If you want to create a volume V of the more dilute 0.2M solution, start with 0.1 V of the concentrated solution and add 0.9 V of H2O.