How do you know what shape the graph in the xy-plane represented by x=3sin(t) and y=2cos(t) is?

3 answers

x/3=sin(t), y/2=cos(t)
x^2/3^2=sin^2(t)
+
y^2/2^2=cos^2(t)
_____________________

x^2/3^2+y^2/2^2=1
this service is so nice make engineering services to coming education learning
xx2qe2qxq2x2qe
Similar Questions
  1. Given that 2cos^2 x - 3sin x -3 = 0, show that 2sin^2 x + 3sin x +1 = 0?Hence solve 2cos^2 x + 4sin x - 3 = 0, giving all
    1. answers icon 2 answers
  2. Find all solutions on the interval [0.2pi)A) -3sin(t)=15cos(t)sin(t) I have no clue... b) 8cos^2(t)=3-2cos(t) All i did was move
    1. answers icon 1 answer
  3. Find the derivative of y with respect to x:y=3sin^4(2-x)^-1 y=[3sin(2-x)^-1]^4 y'=4[3sin(2-x)^-1]^3 (-3cos(2-x)^-1)(-1)
    1. answers icon 0 answers
    1. answers icon 3 answers
more similar questions