x/3=sin(t), y/2=cos(t)
x^2/3^2=sin^2(t)
+
y^2/2^2=cos^2(t)
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x^2/3^2+y^2/2^2=1
How do you know what shape the graph in the xy-plane represented by x=3sin(t) and y=2cos(t) is?
3 answers
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