that's just a number, so
∫3-e^1 dx = (3-e)x + c
I suspect a typo.
how do you integrate
3-e^1?
2 answers
maybe you mean
( 3 - e)^1 dx ???
or maybe
3 dx - e^1 dx ???
anyway the power 1 changes nothing
so it is maybe
(3-e) dx
which is
(3-e) x + C ???
( 3 - e)^1 dx ???
or maybe
3 dx - e^1 dx ???
anyway the power 1 changes nothing
so it is maybe
(3-e) dx
which is
(3-e) x + C ???