How do you find the zeros?

g(x) = x3 – x2 – 4x + 4

1 answer

Use this notation to indicate exponents:

x^3 - x^2 - 4x + 4 = 0
grouping will work

x^2(x - 1) - 4(x - 1) = 0
(x-1)(x^2 - 4) = 0
(x-1)(x+2)(x-2) = 0
so
x = 1 , -2 , +2
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