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How do you find the zeroes of a function and their multiplicities?

Y= (x-2)^3(2x+5)^2

1 answer

If (ax-b)=0, then x = b/a

If (ax-b)^n is a factor, then the root has multiplicity n.

So, your roots are
x = 2, multiplicity=3
x = -5/2, multiplicity=2
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