In your text. In your notes? On the web?
MnO4^- + 8H^+ 5e ==> Mn^+2 + 4H2O is -1.51 volts.
MnO2 + 4H^+ + 2e ==> Mn^+2 + 2H2O is 1.23 volts in my tables.
how do you find the standard electrode potentials of KMnO4 and MnCl2?
and is the standard electrode potential of MnO2 1.28?
1 answer