How do you find the odds if the probability of tossing a total of 7 two number cubes is 1/6.

Answer 1

There are 6x6= 36 possible outcomes of throwing 2 dice, if you keep track of each die (A & B) separately.
The combinations that result in 7 are:
A --B
-----
1 & 6
2 & 5
3 & 4
4 & 3
5 & 2
6 & 1
All outcomes are equally likely. That's 6 combinations that yield a sum of 7 out of 36, and that equals 1/6.

Answer 2

The ODDS in favour of an EVENT
= Prob(EVENT happening) : Prob(EVENT not happening)

prob(a seven) = 1/6
prob (not a seven) = 5/6

so the odds in favour of a seven = (1/6) : (5/6)
= 1:5

in the same way the odd against throwing a seven would be 5:1