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How do you find the lengths of the sides of an isosceles triangle with three medians?

2 answers

Hint:
Call the lengths of medians 3b, 3b and 3a.
The length of the base
= 2√((2b)²-a²)

The length of one of the congruent sides
= 2√((2b)²-b²)
= 2&radc;(3)b

*
= 2√(3)b

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