f=a t^-n
f'= -an t^(-n-1)
how do you find the derivative of
square root of 5 /t^5
3 answers
i already know this rule but im still having trouble solving it
(5/(t^5))^1/2
you can rewrite this as:
(5t^(-5))^1/2
therefore,,
(1/2)*(-25t^-6)*(5t^(-5))^(-1/2)
so there,, =)
you can rewrite this as:
(5t^(-5))^1/2
therefore,,
(1/2)*(-25t^-6)*(5t^(-5))^(-1/2)
so there,, =)