if z = x^2y-y^2-2x
∂z/∂x = 2xy-2
∂z/∂y = x^2-2y
If they are both zero (the stationary point), then
xy=1, so y=1/x
x^2-2/x = 0
x^3-2=0
x = ∛2
so, y=1/∛2
How do you find the coordinates of the stationary points to this implicit differentiation equation?
x^2y = y^2 + 2x
2xy + x^2yy' = 2yy' + 2
y'(x^2y-2y) = 2-2xy
y' =
2(1-xy)
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y(x^2-2)
1 answer
1 answer