How do you find all the solutions of the equation in the interval [0,2π)?

Question

3tan^3x=tanx

Answer 1

tan x (3tan^2 x - 1) = 0
tan x = 0 or tan x = +/- 1/sqrt3 are both solutions
There are four angles that have a tangent of +or- 1/sqrt3, and two angles with a tangent of zero in the [0,2 pi) interval