6x-x^3-x^2
= -x(x^2 + x - 6)
= -x(x+3)(x-2)
How do you factor this completely?
6x-x^3-x^2
2 answers
Factor 6X-X^3-X^2 completely.
Step1. Arrange exponents in decreasing order: -x^3-x^2+6x.
Step2.-X(X^2+X-6)
Step3. -X(X-2)(X+3).
The equation in step2 is not completely
factored, because the trinomial can be
factored into 2 binomials (step 3).
Step1. Arrange exponents in decreasing order: -x^3-x^2+6x.
Step2.-X(X^2+X-6)
Step3. -X(X-2)(X+3).
The equation in step2 is not completely
factored, because the trinomial can be
factored into 2 binomials (step 3).