How do you factor and simplify,

Question

1-sin^3x

and
sec^4x-2sec^2xtan^2x+tan^4x

Answer 1

the first is the difference of two cubes:

(1-a^3)=(1-a)(1+a+a^2)
from...
a3 – b3 = (a – b)(a2 + ab + b2)

the second is very similar to

(a^2-2ab+b^2).....

Answer 2

I'm not positive, but the answer to 1-sin^3 would be (1-sinx)(1+sinx+sin^2x)