Heat lost by water + heat gained by Pt = 0
We call Pt 1; then H2O = 32
[mass H2O x 32 x (Tfinal-Tinitial)] + [mass Pt x 1 x (Tfinal-Tinitial) = 0
Substitute and solve for Tfinal.
How do you do this?
If 100 grams of boiling water at 100 degrees C is poured into a 100 g beaker of platinum at 0 degrees C, an intermediate temperature will result. Knowing that the specific heat of water is about 32 times larger than the specific heat of platinum, approximate the resulting temperate?
2 answers
DrBob222: Can you check my recent lab post. I'm just confused on what numbers to put where because some things aren't given. Lab due tmrw. Please help! Thankyou so much.