"as shown" doesn't work here.
Are there two pens with a common side?
How do you do this?
A farmer has 336 feet of fencing and wants to build two identical pens for his prize-winning pigs. The pens will be arranged as shown. Determine the dimensions of a pen that will maximize its area.
4 answers
Yes
Ok, in your diagram,
let the length of the entire enclosure be y ft
let the width be x ft (there are 3 of these)
3x + 2y = 336
y = (336 - 3x)/2 = 168 - 3x/2
area = xy
= x(168 - 3x/2)
= 168x - (3/2)x^2
this is a downwards opening parabola
the x of the vertex is -168/-3 = 56
then y = 168 - (3/2)(56) = 84
the length is 84 ft, and each of the 3 width = 56 ft
check: 2(84) + 3(56) = 636
let the length of the entire enclosure be y ft
let the width be x ft (there are 3 of these)
3x + 2y = 336
y = (336 - 3x)/2 = 168 - 3x/2
area = xy
= x(168 - 3x/2)
= 168x - (3/2)x^2
this is a downwards opening parabola
the x of the vertex is -168/-3 = 56
then y = 168 - (3/2)(56) = 84
the length is 84 ft, and each of the 3 width = 56 ft
check: 2(84) + 3(56) = 636
hey y'all
the length is 45
width is 30
length is 40 cause its on the brainy duh but since theres 4 adjacent sides that'd be 45*4 which is 180 then u subtract 180 from 360 and you get 180 so you divide that by six for the non adjacent sides
the length is 45
width is 30
length is 40 cause its on the brainy duh but since theres 4 adjacent sides that'd be 45*4 which is 180 then u subtract 180 from 360 and you get 180 so you divide that by six for the non adjacent sides
1 answer