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How do you do these questions, I have all my steps done until the last one:
2x(2x)^2: 2x(4x^2)?
Now do I multiply or add the big numbers?
also Im having trouble on these:
1. x^2(xy)^3: x2(x^3y^3)
2. 3x^2(2x)^3: 3x^2 (8x^3)
3. -2x^2y(3xy^2)^2
4. -(3x)^2: -(9x^2)?
5. 5x(2x^2)^2
6. -3x^2y(xy)^3
7. 2xy^2(3x^2y)^3
Everything is done but the last step, please help, thanks
3 answers
Here are other websites that may have explanations to help:
http://www.aaamath.com/
http://mathforum.org/dr.math/
http://www.aaamath.com/
http://mathforum.org/dr.math/
Not sure what it is you want to do. What is the "last step"? The "big numbers" are just coefficients, and can be moved around as needed, since multiplication is commutative.
x^2(xy)^3: x2(x^3y^3): x^5y^3
3x^2(2x)^3: 3x^2 (8x^3): 3x^2 * 8x^3: 24x^5
-2x^2y(3xy^2)^2: (-2)(x^2y)(9)(x^2y^4): -18x^4y^5
-(3x)^2: -(9x^2): (-1)(9x^2): (-1)(9)x^2: -9x^2
5x(2x^2)^2: (5)(x)(4x^4): 20x^5
-3x^2y(xy)^3: -3x^5y^4
2xy^2(3x^2y)^3: 54x^7y^5
One thing they didn't test was things like
(-3xy^2)^2: (-3)^2 x^2y^4: 9x^2y^4
having a "-" inside the parens can make a difference!
x^2(xy)^3: x2(x^3y^3): x^5y^3
3x^2(2x)^3: 3x^2 (8x^3): 3x^2 * 8x^3: 24x^5
-2x^2y(3xy^2)^2: (-2)(x^2y)(9)(x^2y^4): -18x^4y^5
-(3x)^2: -(9x^2): (-1)(9x^2): (-1)(9)x^2: -9x^2
5x(2x^2)^2: (5)(x)(4x^4): 20x^5
-3x^2y(xy)^3: -3x^5y^4
2xy^2(3x^2y)^3: 54x^7y^5
One thing they didn't test was things like
(-3xy^2)^2: (-3)^2 x^2y^4: 9x^2y^4
having a "-" inside the parens can make a difference!
1 answer