How do you do the inverse of absolute temperature?

My kelvin temperatures are:
298
308
318
328
338
348
358
368
378

Taking the natural log of both sides of both sides of the equation gives ln(k) = ln(A) – E/RT. Thus, a graph of the natural log of the reaction rate constant versus the inverse of the absolute temperature should be linear. Create such a graph to verify this is true.

1 answer

298 = T
inverse is 1/T = 1/298