Asked by Hannah
How do you do the derivative of an inverse trig function?
arcsin (sqrt2/2)??
arcsin (sqrt2/2)??
Answers
Answered by
bobpursley
arcsin(sqrt2/2 ) is a constant. The derivative of a constant is zero.
Answered by
Hannah
oops mixed up 2 questionss haha
Answered by
Hannah
to find an arcsin you would just have to memorize the unit circle right? so arccos of -sqrt3/2 is 5pi/6?
Answered by
bobpursley
yes, that is the easy way.
Answered by
Steve
However, to find the derivative of an inverse trig function, go through the back door, as it were
y = arcsin(x)
sin y = x
cos y y' = 1
y' = 1/cos x = 1/√(1-sin<sup>2</sup>x) = 1/√(1-x<sup>2</sup>)
y = arcsin(x)
sin y = x
cos y y' = 1
y' = 1/cos x = 1/√(1-sin<sup>2</sup>x) = 1/√(1-x<sup>2</sup>)
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