How do you construct a segment that is the square root of 7 inches long since there are no two numbers that you can add together that equal 7 that have equal square. Would one side of the triangle equal 2 and the other the square root of 9?

Answer 1

a^2 + b^2 = c^2 ... (√7)^2 + 3^2 = 4^2

construct a 3" segment with a perpendicular at one end

at the other end strike a 4" radius arc

the arc intersects the perpendicular √7" from the right angle