how do you calculate the pOH of a 0.25M solution of monochloroacetic acetic acid at 25C

Answer 1

You look up the Ka or pKa for the acid:2.87= pKa

or Ka=(x)(x)/(.25-x)

pKa=2p(x)-p(.25-x)

assume x is small..
2.87=2p(x)-p(.25)

p(x)=2.87/2 -1/2 (-.6)

p(H)=1.44+.3=1.74
p(OH)=14-pH