(acid) = 1M x 75/100 = ??
(salt) = 1 M x 25/100 = ??
Plug into the Henderson-Hasselbalch equation.
How do you calculate the PH of a buffer solution prepared by mixing 75 mL of 1.0 M lactic acid and 25 mL of 1.0 M sodium lactate?
3 answers
4.34
the pKa of lactic acid is 3.86
pH=3.86+ log[(25x1.0)÷(75x1.0-3)]
pH = 3.38
the pKa of sodium lactate 3.78
pH=3.78+ log[(25x1.0)÷(75x1.0-3)]
pH = 3.30
pH=3.86+ log[(25x1.0)÷(75x1.0-3)]
pH = 3.38
the pKa of sodium lactate 3.78
pH=3.78+ log[(25x1.0)÷(75x1.0-3)]
pH = 3.30