How do you calculate the horizontal velocity of an object in a projectile problem?

3 answers

it depends on what you have given. If you know a projectile is fired with velocity v at an angle theta, then horizontal velocity is

Vh=VcosTheta
It's weird because I'm only give 25m and 5m in this problem. It looks like this kinda

|
| 5m
|
|_________________
25m

I'm suppose to find the horizontal velocity with this
You dropped it from 5 meters
and it went 25 meters maybe ??
If so:
time to drop 5 meters
5 = (1/2)(9.8)t^2
t = 1.43 seconds
u = 25 m/1.43 s = 17.5 m/s