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How do you balance the equation NH3 + CuO > Cu + H2O + N2

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I notice N goes from -3 to zero oxidation state, and Cu goes from +2 to zero.

so it takes 2N for each 3Cu.

2NH3+3CuO>> 3Cu + 3H2O + N2

2NH3 + 3Cuo -----> 3Cu + 3H2O +N2

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