How do we solve for x and y where y=(1/3)log2(x) and 8^(2y-1) = 2(x-4)

Question

From the 1st one,I got x = 2^(3y) & by substituting it in the 2nd resulted 8^(2y-1) = 2((2)^(3y) - 4)

How to proceed?

Answer 1

ok so far, but messy
Check if the 2nd equation wasn't
8^(2y-1) = 2^(x-4)

Answer 2

Thanks Reiny I solved it