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How do we set up this problem. The product of a number and 6 is decreased by 8. The result is 13 greater than the product of 4 and the same number increased by 3. What is the number?

He set it up like follows:
6N-8=4N+3
6N-4N=8+3
2N=11
N=11/2
but I can't figure out where the 13 should have been in the problem because the answer in my grader is 33/2. We tried adding it to the 6N -8 side or adding it to the other side but nothing comes up with the answer and we can't figure out what we are doing wrong or my grader is wrong. Please help if you can. Thanks

2 answers

6n-8 = 13 + 4(n+3)
6n-8 = 13+4n+12
2n = 33
n = 33/2
Thank you ☺
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