How do we get a random key from a menu_items dict using the random module's choice() function?

Question

random_menu_item = choice(menu_items.keys())

random_menu_item = choice(menu_items.items())

random_menu_item = choice(menu_items)

random_menu_item = choice(menu_items.values())

Answer 1

The correct way to get a random key from a `menu_items` dict using the `random` module's `choice()` function is:

```python
random_menu_item = choice(list(menu_items.keys()))
```

Explanation:
- The `keys()` method of a dictionary returns a view object that contains the keys of the dictionary.
- To use the `choice()` function, we need to provide it with a sequence or iterable.
- Therefore, we need to convert the view object returned by `keys()` into a list using the `list()` function before passing it to `choice()`.

Answer 2

How do we get a random key from a menu_items dict using the random module's choice() function?
random_menu_item = choice(menu_items.keys())

random_menu_item = choice(menu_items.items())

random_menu_item = choice(menu_items)

random_menu_item = choice(menu_items.values())

Answer 3

The correct way to get a random key from a `menu_items` dict using the `random` module's `choice()` function is:

```python
random_menu_item = choice(list(menu_items.keys()))
```

Explanation:
- `menu_items.keys()` returns a view object that contains the keys of the dictionary.
- `choice()` function requires a sequence to choose a random item from, so we need to convert the view object to a list using `list()` function.
- Finally, `choice()` will select a random key from the converted list and assign it to the `random_menu_item` variable.