No.
delta T = i*Kb*m
Since Kb is the same for both, the differences are due to i*m and since m is the same the differences are due to i.
i for C6H12O6 = 1
i for CaCl2 = 3
Look up the van't Hoff factor.
How do the boiling points of 3.0 m C6H12O6 and 3.0 m CaCl2 compare?
A. The boiling point of 3.0 m C6H12O6 is higher.
B. The boiling point of 3.0 m CaCl2 is higher.
C. They are the same.
D. The difference cannot be determined from the information given.
I think the answer is D. Is that correct?
1 answer