-y=4-3x Multiply with(-1)
y=3x+4 (Slope=3)
Remember, any two perpendicular lines are negative reciprocals of each other. So if you're given the slope of 3, you can find the perpendicular slope by this formula:
mp=(-1)/m
where:
m-slope of line y=3x+4
mp is the perpendicular slope
mp=(-1/3)
So now we know the slope of the unknown line is (-1/3) its the negative reciprocal of 3 from the line y=3x+4
Also since the unknown line goes through (12,0), we can find the equation by plugging in this info into the point-slope formula.
Point-Slope Formula:
y-y1=mp(x-x1)
where mp is the slope and (x1,y1) is the given point.
mp=(-1/3)
x1=12
y1=0
y-0=(-1/3)*(x-12)
y=(-1/3)*x+(-1/3)*(-12)
y=(-1/3)*x+4
So the equation of the line that is perpendicular to y=3x+4 and goes through (12,0) is:
y=(-1/3)*x+4
How do I write the equation of the line in standard form given this info:
Perpendicular to 3x - 1y = 4 with an x-intercept of 12 ?
Thanks! :)
1 answer