How do I solve this using the TERM BY TERM method?

If f(x)= (2x^2 - 5x - 3) / (3-x)

find f'(-8).

2 answers

2(-8)^2 = 2*64 = 128
-5(-8) = 40
-3 = -3 now add
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165 = numerator

3 - (-8) = 11

so
165/11
that's f(-8), but we want f'(-8)
f(x) = -(2x+1)