last year = x
this year = x+20
x = 0.75(x+20)
How do I solve this type of problem? How many steps are there.
The cost of a membership at a health club last year was 75% of the cost at the club this year. This year's membership costs $20 more than last year's membership. Find the cost of a membership last year and the cost of a membership this year.
3 answers
Simplifying
x = 0.75(x + 20)
Reorder the terms:
x = 0.75(20 + x)
x = (20 * 0.75 + x * 0.75)
x = (15 + 0.75x)
Solving
x = 15 + 0.75x
Solving for variable 'x'.
Move all terms containing x to the left, all other terms to the right.
Add '-0.75x' to each side of the equation.
x + -0.75x = 15 + 0.75x + -0.75x
Combine like terms: x + -0.75x = 0.25x
0.25x = 15 + 0.75x + -0.75x
Combine like terms: 0.75x + -0.75x = 0.00
0.25x = 15 + 0.00
0.25x = 15
Divide each side by '0.25'.
x = 60
Simplifying
x = 60
Try our website geteasysolution (It wont let me post link)
x = 0.75(x + 20)
Reorder the terms:
x = 0.75(20 + x)
x = (20 * 0.75 + x * 0.75)
x = (15 + 0.75x)
Solving
x = 15 + 0.75x
Solving for variable 'x'.
Move all terms containing x to the left, all other terms to the right.
Add '-0.75x' to each side of the equation.
x + -0.75x = 15 + 0.75x + -0.75x
Combine like terms: x + -0.75x = 0.25x
0.25x = 15 + 0.75x + -0.75x
Combine like terms: 0.75x + -0.75x = 0.00
0.25x = 15 + 0.00
0.25x = 15
Divide each side by '0.25'.
x = 60
Simplifying
x = 60
Try our website geteasysolution (It wont let me post link)
Thanks. Membership last year was $60 and membership this year is $80.