Asked by Mary Ann
How do I solve this problem.
I try just 1 than just 4
nether were right, than I try 4/4r
the Problem is 4Pr
Thank you
I try just 1 than just 4
nether were right, than I try 4/4r
the Problem is 4Pr
Thank you
Answers
Answered by
MathMate
nPr=n!/(n-r)!
4Pr=4!/(4-r)!=24/(4-r)!
unless you know the value of r, this is the furthest we can go.
4Pr=4!/(4-r)!=24/(4-r)!
unless you know the value of r, this is the furthest we can go.
Answered by
Damon
in general for n items taken r at a time
P(n,r) = n!/ (n-r)!
for n = 4 and r at a time
P(4,r) = 4!/(4-r)!
so for 4 taken 1 at a time
4!/3! = 4*3*2*1/(3*2*1) = 4
or for 4 taken 2 at a time
4!/(2)! = 4*3 *2*1/2*1 = 12
Answered by
Mary Ann
thank you Damon
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