How do I solve

Integral of 7/(16-x^2)

I know I must break down (16-x^2) into (x+4)(-x+4), but after I do that what is next?

Using the method of partial fractions, convince yourself that
7/(16-x^2)= (7/8)*[1/(4+x) + 1/(4-x)]
The two additive
terms can be integrated by the method of substitution.
4+x -> u etc. You will end up with terms that are the log of 4+x and 4-x.

Ask a New Question or answer this question.

Similar Questions

The question is:Evaluate the improper integral for a>0. The integral is: the integral from 0 to infinity, of e^(-y/a)dy Can
1. 1 answer
How would I solve the following integral with the substitution rule?Integral of: [(x^3)*(1-x^4)^5]dx Put 1-x^4 = y Then -4x^3 dx
1. 1 answer
Perform long division on the integrand, write the proper fraction as a sum of partial fractions, and evaluate the integral:(inte
1. 1 answer
find integral using table of integrals )integral sin^4xdx this the formula i used integral sin^n xdx =-1/n sin^n-1xcosx +n-1/n
1. 3 answers