How do I solve f(x)=x^3-6x^2+16x-96 using Descartes' Rule of Signs to find the number of positive and negative real roots, along with imaginary roots, but not with a graph?

Answer 1

f(x) has 3 sign changes, so 3 or 1 positive roots
f(-x) has no sign changes, so no negative roots

There might be two complex roots.