how do i solve differential equation dy/dx=3/(2-x) and use graphing utility to graph 3 solutions,one which passes through the point(1,0)

Answer 1

Integrate

dy = 3 dx/(2-x)

y - yo = -3 ln (2-x)+- 3 ln(2-xo)

y = -3 ln[(2-x)/1] = -3 ln (2-x)