Ask a New Question

how do I solve cosh((1+j)/2) to form of a+jb????

1 answer

cosh(x+jy) = cosh x cos y + j sinh x sin y
here x = 1/2
and y = 1/2

Ask a New Question or answer this question.

Similar Questions

what is the anti-derivative on square root of cosh^2(x)?The square root of cosh^2 x is just cosh x, and the integral (or
1. 0 answers
Find the numerical value of each expression. (Round your answers to five decimal places.)(a) cosh 9 (b) cosh(ln 9)
1. 5 answers
How to derive cosh (3x) in terms of cosh (x) and sinh (x) ? Initially I start with 1/2 (e^3x+e^-3x) but I'm stuck from there
1. 2 answers
definite integral of (e^(8x))cosh(8x)dx from 0 to 1/16-I substitued the definition of cosh in, i.e. (e^(8x) + e^(-8x)/2 but i
1. 1 answer

more similar questions