How do I set up the quadratic equation for this problem?

Question

4.0= (2x)^2 / (1.0-x)(1.0-x)

I know how to use the formula, but I have a hard time setting those equation to zero. Please explain step by step.
Thank you

Answer 1

your equation becomes:

4 = 4x^2/(1-x)^2
multiply both sides by (1-x)^2

4(1-x)^2 = 4x^2
4(1 - 2x + x^2) = 4x^2
4 - 8x + 4x^2 = 4x^2
4=8x
x = 1/2