can you solve
10 = 25(.5)^(t/20) where t will be in minutes ?
How do I set-up/solve this problem? Please help me.
The half-life of the radioactive isotope gallium-70 is 20 minutes. If the initial amount of gallium-70 is 25 milligrams, when will 10 milligrams be left?
3 answers
This is what I got..
25(1/2)^(t/20)=10
(1/2)^(t/20)=10/25=2/5
(1/2)^(t/20)=2/5
t/20=log(2/5)/log(1/2)
t=20(log(2/5)/log(1/2))
t=26.44
Is this correct?
25(1/2)^(t/20)=10
(1/2)^(t/20)=10/25=2/5
(1/2)^(t/20)=2/5
t/20=log(2/5)/log(1/2)
t=20(log(2/5)/log(1/2))
t=26.44
Is this correct?
correct, good job.
1 answer