They want me to show that it is equal to 2019
But I don't know how?
How do I prove that integral e^((x^2020)/n))dx where the lim n tends to infinity and the boundaries of the integral is from 0 to 2019
How do I do this??
3 answers
as n→∞, (x^2020)/n → 0
lim ∫ = ∫ lim
so, as n→∞ you have ∫[0,2019] e^0 dx = x[0,2019] = 2019
lim ∫ = ∫ lim
so, as n→∞ you have ∫[0,2019] e^0 dx = x[0,2019] = 2019
Thank you sir