All the online integration calculators I tried said that this cannot be integrated.
Recheck your problem.
How do I integrate tanx (1+sec^4 x)^3/2 dx
My daughter is doing surface area problems, and all the examples assume she knows how to finish it off once we get to the integration....
2 answers
Try substitution:
u=cos(x)
du=-sin(x)dx
Then
∫tanx (1+sec^4 x)^3/2 dx
=∫(1+sec^4 x)^3/2 sin(x) dx / cos(x)
=-∫[(1+(1/u)^4)^3/2 /u] du
But the integration is still ugly!
Rechecking the problem is the first thing to do.
u=cos(x)
du=-sin(x)dx
Then
∫tanx (1+sec^4 x)^3/2 dx
=∫(1+sec^4 x)^3/2 sin(x) dx / cos(x)
=-∫[(1+(1/u)^4)^3/2 /u] du
But the integration is still ugly!
Rechecking the problem is the first thing to do.
0 answers