Is all of u -2 +2u^2
a denominator?
That is (2u-1)(u+1)
So you would be integrating
2u/[(2u-1)(u+1)]
The method of partial fractions can be used.
See
http://www.math.ucdavis.edu/~kouba/CalcTwoDIRECTORY/partialfracdirectory/PartialFrac.html
how do i integrate
2u du /u-2+2u^2
so i used subsitution rule?
or can i used integration by parts and how? thanks in adnvace
1 answer