How do i get 2 consecutive numbers (pair numbers) that they product is 272?

Question

4X² + 4X - 272=0

Answer 1

h, h +1

h(h+1) = 272

h^2 + h = 272

h^2 + h -272 = 272-272

h^2 + h -272 = 0

(h -16)(h + 17) = 0

h = 16
h = -17

-16, -17, and 16, 17

Answer 2

x = first number

y = second number

y = x + 1

x * y = 272

x * ( x + 1 ) = 272

x ^ 2 + x = 272

x ^ 2 + x - 272 = 0

Solutions :

x = - 17

and

x = 16

For x = - 17

y = x + 1 = - 17 + 1 = - 16

x * y = - 17 * ( - 16 ) = 272

For x = 16

y = x + 1 = 16 + 1 = 17

x * y = 16 * 17 = 272

So solutions are :

- 17 and - 16

and

16 and 17

Answer 3

Yes.Both are all solution.

Proof

x(x+1)= 272

16(16+1) = 272
16(17) =272
272 = 272

-17(-17+1) = 272

-17(-16)= 272
272 = 272