How do I find x and y in the following equation:

222. 4
86 Rn - 2 He + X

228. 0
-1 e. + y
88ra

1 answer

I can't decipher what you have because of the spacing and extra lines. Do this. Write the atomic number FIRST, then the element symbol, then the mass number. For example, Radon 222 would be written as 86Rn222; the alpha particle (He nucleus) is 2He4, etc.
I think you may have
86Rn222 - 2He4 + but the rest of it I don't see. Unless it may be TWO problems. The first one may be
86Rn222 - 2He4 ==> X. If that's the first question, just make the numbers to left add up on both sides and the numbers on the right add up on both sides. In chemical terms you are making the atomic numbers add on (the left numbers) and the mass numbers add up (the right numbers).
86Rn222 - 2He4 ==> 84X218, then you look on the periodic table and see that element number 84 is Po.
Similar Questions
  1. N 5 22x2 1 76x 1 430Use the equation to find N for each year in the table. (b) Discuss how well this equation approximates the
    1. answers icon 1 answer
    1. answers icon 1 answer
  2. 1. Find the equation of the asymptotic of the hyperbolex^2/9 - y^2/ 4 = 1. 2. Given the equation of a function 2x^2 + 5y^2 - 16x
    1. answers icon 1 answer
    1. answers icon 1 answer
more similar questions