Asked by Victoria
How do I find x and y in the following equation:
222. 4
86 Rn - 2 He + X
228. 0
-1 e. + y
88ra
222. 4
86 Rn - 2 He + X
228. 0
-1 e. + y
88ra
Answers
Answered by
DrBob222
I can't decipher what you have because of the spacing and extra lines. Do this. Write the atomic number FIRST, then the element symbol, then the mass number. For example, Radon 222 would be written as 86Rn222; the alpha particle (He nucleus) is 2He4, etc.
I think you may have
86Rn222 - 2He4 + but the rest of it I don't see. Unless it may be TWO problems. The first one may be
86Rn222 - 2He4 ==> X. If that's the first question, just make the numbers to left add up on both sides and the numbers on the right add up on both sides. In chemical terms you are making the atomic numbers add on (the left numbers) and the mass numbers add up (the right numbers).
86Rn222 - 2He4 ==> 84X218, then you look on the periodic table and see that element number 84 is Po.
I think you may have
86Rn222 - 2He4 + but the rest of it I don't see. Unless it may be TWO problems. The first one may be
86Rn222 - 2He4 ==> X. If that's the first question, just make the numbers to left add up on both sides and the numbers on the right add up on both sides. In chemical terms you are making the atomic numbers add on (the left numbers) and the mass numbers add up (the right numbers).
86Rn222 - 2He4 ==> 84X218, then you look on the periodic table and see that element number 84 is Po.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.