How do I find the Volume of the Solid of revolution generated by revolving the region bounded by the graphs of the given equations about the indicated line.
y= 1/x, y=0, x=1, x=0; about the line y=6
5 answers
I suspect a typo. The given region is unbounded. x=0 is an asymptote.
oh jeez yeah it is x=4
there is a typo, these are the equations:
y=1/x, y=0, x=1, x=4; about y=6
y=1/x, y=0, x=1, x=4; about y=6
That's better.
Using discs of thickness dx,
v = ∫[1,4] π(R^2-r^2) dx
where R=6 and r = 6-y
Thus,
v = ∫[1,4] π(6^2 - (6 - 1/x)^2) dx
Using discs of thickness dx,
v = ∫[1,4] π(R^2-r^2) dx
where R=6 and r = 6-y
Thus,
v = ∫[1,4] π(6^2 - (6 - 1/x)^2) dx
Thank you!
1 answer