How do I find the value of d^2y/dx^2 for the function defined implicitly by xy^2 + y = 2 at the point (1,-2)?

Answer 1

xy^2+y=2

y^2 dx + 2xy dy+dy=0
dy/dx ( 2xy+1)=y^2
dy/dx= y^2(1/(2xy+1)

dy"/dx"= 2y/(2xy+1) -y^2/(2xy+1)^2 * (2y*xdy/dx+2y)

Put for dy/dx y^2/(2xy+1)

then put number (1,-2)

CHECK MY WORK, I have a headache (Elm pollen).