How do I find the slope of the line through (-9, -10) and (-2,-5)?
2 answers
the slope is, as always, ∆y/∆x = (-5-(-10))/(-2-(-9)) = 5/7
for two points, (x1,y1) and (x2,y2)
the slope = (y2-y1)/(x2-x1)
apply it to your two points, show me your work
the slope = (y2-y1)/(x2-x1)
apply it to your two points, show me your work