Consider the function
u = │x/(1+x^2)│
it looks like birdwings, with (0,0) a cusp, the curve rising to a maximum of (1,1/2) and then dropping again to approach the x-axis with the x-axis as an asymptote. It is symmetric about the y-axis.
so then you are looking at ln u
u lies between 0 and 1/2 , so ln u will always be negative.
ln 1/2 = -.693 and for all other of u values which will be less than 1/2 ln u will be less than -.693
as u --> 0 ln u approaches negative infinity
so the range is ≤ -.693
how do I find the range of a natural log like
ln | x/(1+x^2) |
1 answer
1 answer